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| 1 | +#!/usr/bin/env python |
| 2 | + |
| 3 | +import numpy as np |
| 4 | + |
| 5 | +#----------------------------------------------------------------------------- |
| 6 | +# Define some useful constants |
| 7 | +#----------------------------------------------------------------------------- |
| 8 | + |
| 9 | +cKB_ = 1.38064852e-23 |
| 10 | +cRE_ = 6371.0 |
| 11 | +cG_ = 9.81 |
| 12 | +cAMU_ = 1.6726219e-27 |
| 13 | +cH_ = 6.6261e-34 |
| 14 | +cC_ = 2.9979e8 |
| 15 | +cE_ = 1.6022e-19 |
| 16 | +cD2R_ = 3.1415927 / 180.0 |
| 17 | + |
| 18 | +#----------------------------------------------------------------------------- |
| 19 | +# calculate the scale height, which is KT/mg, where: |
| 20 | +# k - boltzmann's constant |
| 21 | +# t = temperature |
| 22 | +# m = mass |
| 23 | +# g = gravity |
| 24 | +# Feed in |
| 25 | +#----------------------------------------------------------------------------- |
| 26 | + |
| 27 | +def calc_scale_height(mass_in_amu, alt_in_km, temp_in_k): |
| 28 | + |
| 29 | + gravity = cG_ * (cRE_ / (cRE_ + alt_in_km)) |
| 30 | + mass_in_kg = mass_in_amu * cAMU_ |
| 31 | + h_in_km = cKB_ * temp_in_k / mass_in_kg / gravity / 1000.0; |
| 32 | + |
| 33 | + return h_in_km |
| 34 | + |
| 35 | +#----------------------------------------------------------------------------- |
| 36 | +# Calculate a hydrostatic solution: |
| 37 | +# n(i+1) = n(i) * t(i)/t(i+1) * exp(dz / H) |
| 38 | +# where: |
| 39 | +# n = density |
| 40 | +# t = temperature |
| 41 | +# dz = delta-z (delta altitude) |
| 42 | +# H = scale-height |
| 43 | +#----------------------------------------------------------------------------- |
| 44 | + |
| 45 | +def calc_hydrostatic(density_bc, scale_height_in_km, temp_in_k, alt_in_km): |
| 46 | + |
| 47 | + nAlts = len(alt_in_km) |
| 48 | + density = np.zeros(nAlts) |
| 49 | + |
| 50 | + # define our boundary condition |
| 51 | + density[0] = density_bc |
| 52 | + for iAlt in range(1, nAlts): |
| 53 | + tRatio = temp_in_k[iAlt - 1] / temp_in_k[iAlt] |
| 54 | + dz = alt_in_km[iAlt] - alt_in_km[iAlt - 1] |
| 55 | + h = scale_height_in_km[iAlt] |
| 56 | + density[iAlt] = density[iAlt-1] * tRatio * np.exp(-dz / h) |
| 57 | + |
| 58 | + return density |
| 59 | + |
| 60 | +#----------------------------------------------------------------------------- |
| 61 | +# EUVAC - take F107 and F107a and return solar spectrum |
| 62 | +# See Schunk and Nagy, page 259 |
| 63 | +#----------------------------------------------------------------------------- |
| 64 | + |
| 65 | +def EUVAC(f74113, afac, f107, f107a): |
| 66 | + p = (f107 + f107a)/2.0 |
| 67 | + if (p < 80): |
| 68 | + p = 80.0 |
| 69 | + intensity = f74113 * (1.0 + afac * (p-80)) |
| 70 | + return intensity |
| 71 | + |
| 72 | +#----------------------------------------------------------------------------- |
| 73 | +# Take a wavelength in m and convert it to energy in Joules: |
| 74 | +# e = plank's constant * speed of light / wavelength |
| 75 | +#----------------------------------------------------------------------------- |
| 76 | + |
| 77 | +def convert_wavelength_to_joules(wavelength): |
| 78 | + energy = cH_ * cC_ / wavelength |
| 79 | + return energy |
| 80 | + |
| 81 | +#----------------------------------------------------------------------------- |
| 82 | +# Calculate Tau for a given species, given: |
| 83 | +# - solar zenity angle (in degrees) |
| 84 | +# - density in /m3 |
| 85 | +# - scale height in km |
| 86 | +# - cross sections in /m2 |
| 87 | +#----------------------------------------------------------------------------- |
| 88 | + |
| 89 | +def calc_tau(SZA_in_deg, density_in_m3, scale_height_in_km, cross_section): |
| 90 | + |
| 91 | + # We are only going to do this for a single wavelength for now! |
| 92 | + |
| 93 | + cs = cross_section[0] |
| 94 | + |
| 95 | + # convert scale height to m: |
| 96 | + h = scale_height_in_km * 1000.0 |
| 97 | + |
| 98 | + # convert SZA to radians: |
| 99 | + sza = SZA_in_deg * cD2R_ |
| 100 | + |
| 101 | + # calculate integrated density (which is density * scale height): |
| 102 | + integrated_density = density_in_m3 * h |
| 103 | + |
| 104 | + nWaves = len(cross_section) |
| 105 | + nAlts = len(density_in_m3) |
| 106 | + tau = np.zeros((nWaves, nAlts)) |
| 107 | + |
| 108 | + # calculate Tau: |
| 109 | + iWave = 5 |
| 110 | + tau[iWave][:] = integrated_density * cross_section[iWave] |
| 111 | + |
| 112 | + return tau |
| 113 | + |
| 114 | +#----------------------------------------------------------------------------- |
| 115 | +# Calculate energy deposition as a function of altitude, given: |
| 116 | +# - density of a given species in /m3 as a function of altitude |
| 117 | +# - intensity at infinity as a function of wavelength |
| 118 | +# - tau as a function of wavelength and altitude |
| 119 | +# - cross_section of the given species as a function of wavelength |
| 120 | +# - energies of the wavelengths |
| 121 | +# - efficiency of the heating (say 30%) |
| 122 | +#----------------------------------------------------------------------------- |
| 123 | + |
| 124 | +def calculate_Qeuv(density_in_m3, |
| 125 | + intensity_inf, |
| 126 | + tau, |
| 127 | + cross_section, |
| 128 | + energies, |
| 129 | + efficiency): |
| 130 | + |
| 131 | + nAlts = len(density_in_m3) |
| 132 | + nWaves = len(intensity_inf) |
| 133 | + |
| 134 | + Qeuv = np.zeros(nAlts) |
| 135 | + |
| 136 | + iWave = 5 |
| 137 | + |
| 138 | + # intensity is a function of altitude (for a given wavelength): |
| 139 | + intensity = intensity_inf[iWave] * np.exp(-tau[iWave][:]) |
| 140 | + Qeuv = Qeuv + \ |
| 141 | + efficiency * \ |
| 142 | + density_in_m3 * \ |
| 143 | + intensity * \ |
| 144 | + cross_section[iWave] * \ |
| 145 | + energies[iWave] |
| 146 | + |
| 147 | + return Qeuv |
| 148 | + |
| 149 | +#----------------------------------------------------------------------------- |
| 150 | +# calculate rho given densities of O (and N2 and O2) |
| 151 | +#----------------------------------------------------------------------------- |
| 152 | + |
| 153 | +def calc_rho(density_o, mass_o): |
| 154 | + rho = density_o * mass_o * cAMU_ |
| 155 | + return rho |
| 156 | + |
| 157 | +#----------------------------------------------------------------------------- |
| 158 | +# calculate cp. We have hard coded this to be 1500, which is for O, but |
| 159 | +# we could pass densities and vibrational states and get the real Cp. |
| 160 | +#----------------------------------------------------------------------------- |
| 161 | + |
| 162 | +def calculate_cp(): |
| 163 | + cp = 1500.0 |
| 164 | + return cp |
| 165 | + |
| 166 | +#----------------------------------------------------------------------------- |
| 167 | +# calculate dT/dt from Q and rho: |
| 168 | +#----------------------------------------------------------------------------- |
| 169 | + |
| 170 | +def convert_Q_to_dTdt(Qeuv, rho, cp): |
| 171 | + dTdt = Qeuv / (rho * cp) |
| 172 | + return dTdt |
| 173 | + |
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