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printLevelOrder.cpp
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94 lines (71 loc) · 1.55 KB
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#include<iostream>
#include<stdlib.h>
using namespace std;
/*
Using recursion it holds all the node values such that they print when the level returns to 1.
1 ==> 1 ===> PRINT 1
/ \
2 3 ==> 2 ==> PRINT 2 3
/ \ / \
4 5 6 7 ==> 3 ==> PRINT 4 5 6 7
*/
struct Node{
int data;
struct Node *left;
struct Node *right;
};
struct Node* root = NULL;
struct Node *newNode(int data){
struct Node* temp = (struct Node*) malloc ( sizeof(struct Node));
temp->data = data;
temp->left = NULL;
temp->right = NULL;
return temp;
}
int height(struct Node* root){
if(root == NULL){
return 0;
}
int lheight = height(root->left);
int rheight = height(root->right);
if(lheight > rheight){
return lheight+1;
}
return rheight + 1;
}
void levelOrder(struct Node * root,int level)
{
if(root == NULL)
{
return ;
}
if(level == 1)
{
printf("%d -> ",root->data);
}
if(level > 1)
{
levelOrder(root->left,level-1);
levelOrder(root->right,level-1);
}
}
void printLevelOrder(struct Node* root){
int treeHeight = height(root);
int i;
for(i = 1 ; i <= treeHeight ; i++)
{
levelOrder(root,i);
printf("\n");
}
}
int main()
{
struct Node* root = newNode(1);
root->left = newNode(2);
root->right = newNode(3);
root->left->left = newNode(4);
root->left->right = newNode(5);
root->right->left = newNode(6);
root->right->right = newNode(7);
printLevelOrder(root);
}