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104MaximumDepthofBinaryTree.py
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65 lines (49 loc) · 1.37 KB
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"""
Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Note: A leaf is a node with no children.
Example:
Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its depth = 3.
"""
"""
Comments
"""
"""
My
"""
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution:
def maxDepth(self, root: TreeNode) -> int:
if root is None:
return 0
return 1 + max(self.maxDepth(root.left), self.maxDepth(root.right))
"""
Fast
"""
class Solution:
def getMax(node, currentDepth) -> 'int':
# basecase leafnode
if node.left == None and node.right == None:
return currentDepth
else:
if node.left == None:
return Solution.getMax(node.right, currentDepth + 1)
elif node.right == None:
return Solution.getMax(node.left, currentDepth + 1)
else:
return max(Solution.getMax(node.left, currentDepth + 1), Solution.getMax(node.right, currentDepth + 1))
def maxDepth(self, root: 'TreeNode') -> 'int':
if root == None:
return 0
return Solution.getMax(root, 1)