Given a number represented as an array of digits, plus one to the number.
高精度加法。
{% if book.java %} {% codesnippet "./code/plus-one."+book.suffix, language=book.suffix %}{% endcodesnippet %} {% endif %}
{% if book.cpp %}
// 时间复杂度O(n),空间复杂度O(1)
class Solution {
public:
vector<int> plusOne(vector<int> &digits) {
add(digits, 1);
return digits;
}
private:
// 0 <= digit <= 9
void add(vector<int> &digits, int digit) {
int c = digit; // carry, 进位
for (auto it = digits.rbegin(); it != digits.rend(); ++it) {
*it += c;
c = *it / 10;
*it %= 10;
}
if (c > 0) digits.insert(digits.begin(), 1);
}
};{% endif %}