D.cpp

/*One day, Ali Baba had an easy puzzle that he couldn't solve. The puzzle consisted of 4
 numbers and his task was to check whether he could get the fourth number using arithmetic operators (+,−,×) 
 between the other three numbers; so that each operator is used only once.

              a□b□c=d
Can you solve this tricky puzzle for him?
Input
Only one line containing four numbers a, b, cand d(−109≤a,b,c≤109),(−1018≤d≤1018).
Output
Print "YES" (without quotes) if you get the fourth number using arithmetic operators, otherwise, print "NO" (without quotes).*/

#include <iostream>
using namespace std;

int main() {
    long long a,b,c,d;
    cin>>a>>b>>c>>d;

    if (a+b - c == d) { cout << "YES"; return 0; }

    if (a+b * c == d) { cout << "YES"; return 0; }
   
    if (a - b + c == d) { cout << "YES"; return 0; }

    if (a - b * c == d) { cout << "YES"; return 0; }
    
    if (a * b + c == d) { cout << "YES"; return 0; }

    if (a * b - c == d) { cout << "YES"; return 0; }

   else{ cout << "NO";}

    return 0;
}