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Leetcode_15_3Sum.java
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62 lines (50 loc) · 1.65 KB
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/*
* To change this license header, choose License Headers in Project Properties.
* To change this template file, choose Tools | Templates
* and open the template in the editor.
*/
/**
*
* @author KD
*
*
* 15. 3Sum
*
* Given an array nums of n integers, are there elements a, b, c in nums such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note:
The solution set must not contain duplicate triplets.
Example:
Given array nums = [-1, 0, 1, 2, -1, -4],
A solution set is:
[
[-1, 0, 1],
[-1, -1, 2]
]
*/
import java.util.*;
public class Leetcode_15_3Sum {
public List<List<Integer>> threeSum(int[] nums) {
List<List<Integer>> list = new ArrayList<>();
Arrays.sort(nums); // [-4, -1, -1, 0, 1, 2]
for (int i = 0; i < nums.length - 2; i++) {
if (i == 0 || nums[i] > nums[i-1]) {
int low = i + 1;
int high = nums.length - 1;
while (low < high) {
if (nums[i] + nums[low] + nums[high] == 0) {
list.add(new ArrayList<>(Arrays.asList(nums[i], nums[low], nums[high])));
}
if (nums[i] + nums[low] + nums[high] < 0) {
int oldLow = low;
while (nums[low] == nums[oldLow] && low < high) low++;
}
else {
int oldHigh = high;
while (nums[high] == nums[oldHigh] && low < high) high--;
}
}
}
}
return list;
}
}