Optional chaining, CallChain error

[acd02]

TypeScript Version: 3.7.0-beta

Search Terms:
Optional chaining, CallChain

Code

function find<T>(fun: (_: T) => boolean) {
  return (arr: T[]) => arr.find(fun)
}

type Item = {
  label: string
  id: number
}

const items: Item[] = [
  { label: 'one', id: 1 },
  { label: 'two', id: 2
]

const upperCasedlabel = items.find(i => i.id === 1)?.label.toUpperCase() // ONE ✅

// despite the fact that I don't have any ts warning/error, the expression below fails at runtime.
// 👇 does not work, getting this error -> Debug Failure. False expression: Cannot update a CallChain using updateCall. Use updateCallChain instead.
const altUpperCasedlabel = find<Item>(i => i.id === 1)(items)?.label.toUpperCase() ❌

// When I break this into two steps, it works
const maybeItem = find<Item>(i => i.id === 1)(items)
const altUpperCasedlabel = maybeItem?.label.toUpperCase() // ONE ✅

// This also works
const altLabel = find<Item>(i => i.id === 1)(items)?.label // one ✅

Expected behavior:
I'm expecting the first expression altLabel to work, without the need to break the process into two steps

Actual behavior:

Getting an error, Debug Failure. False expression: Cannot update a CallChain using updateCall. Use updateCallChain instead.

Playground Link:

Related Issues:

[Burgov]

The error seems to be back in 20191018. Runs fine in 20191017