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39 lines (33 loc) · 1.09 KB
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/** Project Euler.net
*
* PROBLEM 6:
* The sum of the squares of the first ten natural numbers is,
* 1^2 + 2^2 + ... + 10^2 = 385
*
* The square of the sum of the first ten natural numbers is
* (1 + 2 + ... + 10)^2 = 55^2 = 3025
*
* Hence the difference between the sum of the squares of the first
* ten natural numbers and the square of the sum is 3025 − 385 = 2640.
*
* Find the difference between the sum of the squares of the first
* one hundred natural numbers and the square of the sum.
*
* ANSWER:
*
*
* @author
* Natalie Kerby :: ndkerby@gmail.com
*/
import math.MATH;
import java.util.*;
public class SumSquareDifference {
public static final int START_NUMBER = 1;
public static final int END_NUMBER = 100;
public static void main(String[] args) {
int sumOfSquares = MATH.sumOfSquares(START_NUMBER, END_NUMBER);
int squareOfSums = MATH.squareOfSum(START_NUMBER, END_NUMBER);
int difference = squareOfSums - sumOfSquares;
System.out.println("Difference of sum of squares: " + difference);
}
}