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Day_08.py
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231 lines (176 loc) · 3.65 KB
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#!/usr/bin/env python
# coding: utf-8
# # Question 22
#
# ### **Question:**
#
# > **_Write a program to compute the frequency of the words from the input. The output should output after sorting the key alphanumerically._**
#
# > **_Suppose the following input is supplied to the program:_**
#
#
# New to Python or choosing between Python 2 and Python 3? Read Python 2 or Python 3.
#
#
# > **_Then, the output should be:_**
#
# ```
# 2:2
# 3.:1
# 3?:1
# New:1
# Python:5
# Read:1
# and:1
# between:1
# choosing:1
# or:2
# to:1
# ```
#
# ---
#
# ### Hints
#
# > **_In case of input data being supplied to the question, it should be assumed to be a console input._**
#
# ---
#
#
#
# **Solutions:**
# In[1]:
ss = input().split()
word = sorted(set(ss)) # split words are stored and sorted as a set
for i in word:
print("{0}:{1}".format(i, ss.count(i)))
# **OR**
# In[2]:
ss = input().split()
dict = {}
for i in ss:
i = dict.setdefault(
i, ss.count(i)
) # setdefault() function takes key & value to set it as dictionary.
dict = sorted(
dict.items()
) # items() function returns both key & value of dictionary as a list
# and then sorted. The sort by default occurs in order of 1st -> 2nd key
for i in dict:
print("%s:%d" % (i[0], i[1]))
# **OR**
# In[3]:
ss = input().split()
dict = {
i: ss.count(i) for i in ss
} # sets dictionary as i-> split word & ss.count(i) -> total occurrence of i in ss
dict = sorted(
dict.items()
) # items() function returns both key & value of dictionary as a list
# and then sorted. The sort by default occurs in order of 1st -> 2nd key
for i in dict:
print("%s:%d" % (i[0], i[1]))
# **OR**
# In[4]:
from collections import Counter
ss = input().split()
ss = Counter(ss) # returns key & frequency as a dictionary
ss = sorted(ss.items()) # returns as a tuple list
for i in ss:
print("%s:%d" % (i[0], i[1]))
# **Solution by: AnjanKumarG**
# In[5]:
from pprint import pprint
p = input().split()
pprint({i: p.count(i) for i in p})
# ---
#
# # Question 23
#
# ### **Question:**
#
# > **_Write a method which can calculate square value of number_**
#
# ---
#
# ### Hints:
#
#
# Using the ** operator which can be written as n**p where means n^p
#
#
# ---
#
#
#
# **Solutions:**
# In[6]:
n = int(input())
print(n ** 2)
# ---
#
# # Question 24
#
# ### **Question:**
#
# > **_Python has many built-in functions, and if you do not know how to use it, you can read document online or find some books. But Python has a built-in document function for every built-in functions._**
#
# > **_Please write a program to print some Python built-in functions documents, such as abs(), int(), raw_input()_**
#
# > **_And add document for your own function_**
#
# ### Hints:
#
#
# The built-in document method is __doc__
#
#
# ---
#
#
#
# **Solutions:**
# In[7]:
print(str.__doc__)
print(sorted.__doc__)
def pow(n, p):
"""
param n: This is any integer number
param p: This is power over n
return: n to the power p = n^p
"""
return n ** p
print(pow(3, 4))
print(pow.__doc__)
# ---
#
# # Question 25
#
# ### **Question:**
#
# > **_Define a class, which have a class parameter and have a same instance parameter._**
#
# ---
#
# ### Hints:
#
#
# Define an instance parameter, need add it in __init__ method.You can init an object with construct parameter or set the value later
#
#
# ---
#
#
#
# **Solutions:**
# In[8]:
class Car:
name = "Car"
def __init__(self, name=None):
self.name = name
honda = Car("Honda")
print(f"{Car.name} name is {honda.name}")
toyota = Car()
toyota.name = "Toyota"
print(f"{Car.name} name is {toyota.name}")
# ---