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homework_2_debug.py
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285 lines (217 loc) · 9.58 KB
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import numpy as np
import matplotlib.pyplot as plt
import matplotlib.cm as cm
import random
def rosenbrock_fun(x):
x1, x2 = x
""" This function returns the output of the Rosenbrock function."""
return 100 * ((x2 - x1 ** 2) ** 2) + (1 - x1) ** 2
def rosenbrock_gradient(x):
x1, x2 = x
""" return [df/dx1 df/dx2]"""
dfx1 = -400 * x2 * x1 + 400 * (x1 ** 3) - 2 + 2 * x1
dfx2 = 200 * x2 - 200 * (x1 ** 2)
return np.array([dfx1, dfx2])
def rosenbrock_hessian(x):
x1, x2 = x
""" return [d2f/dx1^2 d2f/dx1dx2
d2f/dx1dx2 d2f/dx2^2]"""
h = np.zeros((2, 2))
h[0, 0] = -400 * x2 + 1200 * (x1 ** 2) + 2
h[0, 1] = -400 * x1
h[1, 0] = -400 * x1
h[1, 1] = 200
return h
def pk_steepest_descent(gradient):
""" search direction for steepest decent."""
return np.array(-1 * gradient / np.linalg.norm(gradient))
def pk_newton(gradient, hessian):
""" search direction for Newton's method."""
h_inv = np.linalg.inv(hessian)
return -np.matmul(h_inv, gradient)
def phi_function(alpha, pk, xk):
""" phi(alpha) = f(xk + alpha*pk)"""
x = xk + alpha * pk
return rosenbrock_fun(x)
def phi_prime(pk, xk):
return np.dot(rosenbrock_gradient(xk), pk)
def hermite(alpha_0, alpha_1, pk, xk):
"""interpolate phi(a0), phi'(a0), phi(a1), phi'(a1)"""
d1 = phi_prime(pk, xk + alpha_0 * pk) + phi_prime(pk, xk + alpha_1 * pk) - 3 * \
(phi_function(alpha_0, pk, xk) - phi_function(alpha_1, pk, xk)) / (alpha_0 - alpha_1)
d2 = np.sign(alpha_1 - alpha_0) * np.sqrt(
d1 ** 2 - phi_prime(pk, xk + alpha_0 * pk) * phi_prime(pk, xk + alpha_1 * pk))
frac = (phi_prime(pk, xk + alpha_1 * pk) + d2 - d1) / \
(phi_prime(pk, xk + alpha_1 * pk) - phi_prime(pk, xk + alpha_0 * pk) + 2 * d2)
return alpha_1 - (alpha_1 - alpha_0) * frac
def quadradic_interp(alpha_0, pk, xk):
""" interpolate over phi(0), phi'(0), phi(alpha_0)"""
top = (alpha_0 ** 2) * (phi_prime(pk, xk))
bottom = (phi_function(alpha_0, pk, xk) - phi_function(0, pk, xk) - alpha_0 * phi_prime(pk, xk))
return - top / (2 * bottom)
def cubic_interp(alpha_0, alpha_1, xk, pk):
# interpolate to the 3rd order
# over the points: phi(0), phi'(0), phi(alpha_0), phi(alpha_1)
# the cubic function is in this form:
# phi_c(alpha) = a*alpha^3 + b* alpha^2 + alpha*phi'(0) + phi(0)
coeff = 1 / ((alpha_0 ** 2) * (alpha_1 ** 2) * (alpha_1 - alpha_0))
mat_1 = np.zeros((2, 2))
mat_1[0, 0] = alpha_0 ** 2
mat_1[0, 1] = -alpha_1 ** 2
mat_1[1, 0] = -alpha_0 ** 3
mat_1[1, 1] = -alpha_1 ** 3
mat_2 = np.zeros(2)
mat_2[0] = phi_function(alpha_1, pk, xk) - phi_function(0, pk, xk) - alpha_1 * phi_prime(pk, xk)
mat_2[1] = phi_function(alpha_0, pk, xk) - phi_function(0, pk, xk) - alpha_0 * phi_prime(pk, xk)
ab_vec = coeff * np.matmul(mat_1, mat_2)
a = ab_vec[0]
b = ab_vec[1]
return (-b + np.sqrt(b ** 2 - 3 * a * phi_prime(pk, xk))) / (3 * a)
def interpolation(alpha_0, alpha_1, xk, pk):
try:
alpha_star = hermite(alpha_0, alpha_1, pk, xk)
except:
return None
if alpha_star <= 0:
return None
# if phi_function(alpha_star, pk, xk) > phi_function(alpha_1, pk, xk) or \
# phi_function(alpha_star, pk, xk) > phi_function(alpha_0, pk, xk):
# return None --> accounting for concave poly.
# alpha_range = np.linspace(alpha_0, alpha_1, 25)
# phi_vals = np.zeros(25)
# for ii in range(25):
# phi_vals[ii] = phi_function(alpha_range[ii], pk, xk)
# plt.plot(alpha_range, phi_vals)
# plt.scatter(alpha_star, phi_function(alpha_star, pk, xk))
# plt.show()
return hermite(alpha_0, alpha_1, pk, xk)
def zoom(alpha_low, alpha_high, xk, pk, c1, c2):
""" find xj in the interval of alpha_low and alpha_high. """
max_iter = 10
k = 0
while max_iter > k:
if abs(alpha_low - alpha_high) < 1e-8: # safeguard.
return None
if phi_function(alpha_high, pk, xk) < phi_function(alpha_low, pk, xk):
return None
# interpolate to find xj between alpha_low and alpha_high
alpha_j = interpolation(alpha_0=alpha_low, alpha_1=alpha_high, xk=xk, pk=pk)
# if interpolation fails:
if alpha_j is None:
alpha_j = (alpha_high - alpha_low) / 2
# compute phi(xj)
res = phi_function(alpha_j, pk, xk)
# test the Armijo condition.
if (res > phi_function(0, pk, xk) + c1 * alpha_j * phi_prime(pk, xk)) or (
res >= phi_function(alpha_low, pk, xk)):
alpha_high = alpha_j
else:
# compute phi_prime(x_j)
if np.abs(phi_prime(pk, xk + alpha_j * pk)) <= -c2 * phi_prime(pk, xk):
# satisfy the curvature condition.
return alpha_j
if phi_prime(pk, xk + alpha_j * pk) * (alpha_high - alpha_low) >= 0:
alpha_high = alpha_low
alpha_low = alpha_j
k += 1
return None
def my_line_search(c1, c2, pk, xk, old_x=None, alpha_0=0, alpha_max=1, method="sd"):
"""Find alpha that satisfies strong Wolfe conditions."""
phi0 = phi_function(0, pk, xk)
dphi0 = phi_prime(pk, xk)
# choose alpha_1
if old_x is not None and dphi0 != 0 and method == "sd":
alpha_1 = min(1.0, 1.01 * 2 * (rosenbrock_fun(xk) - rosenbrock_fun(old_x)) / dphi0)
else:
alpha_1 = 1.0
if alpha_1 <= 0:
alpha_1 = 1.0
if alpha_max is not None:
alpha_1 = min(alpha_1, alpha_max)
alpha_vec = [alpha_0, alpha_1]
i = 1
while True:
# alpha i = ai
alpha_i = alpha_vec[i]
# compute phi(ai)
phi_i = phi_function(alpha_i, pk, xk)
# Armijo condition.
if phi_i > phi0 + c1 * alpha_i * dphi0 \
or (i > 1 and phi_function(alpha_i, pk, xk) >= phi_function(alpha_vec[i - 1], pk, xk)):
return zoom(alpha_low=alpha_vec[i - 1], alpha_high=alpha_vec[i], xk=xk, pk=pk, c1=c1, c2=c2), i
# compute phi prime at alpha i (ai).
phi_prime_alpha_i = phi_prime(pk, xk + alpha_i * pk)
# curvature condition.
if abs(phi_prime_alpha_i) <= -c2 * dphi0:
return alpha_i, i
if phi_prime_alpha_i >= 0:
return zoom(alpha_low=alpha_i, alpha_high=alpha_vec[i - 1], xk=xk, pk=pk, c1=c1, c2=c2), i
alpha_vec.append(random.uniform(alpha_i, alpha_max))
i += 1
def find_local_minimum(x0, c1, c2, alpha, p, tol=1e-8, print_num=None, method="sd", save_xk=True):
""" Find the local minimum point x* using backtracking line search that will satisfy Armijo-Goldstein inequality.
The avilable methods: Newton and Steepest Descent. Default is Steepest descent.
x0 - initial guess for x*.
c1 - the slope of Armijo-Goldstein line.
alpha - initial step size.
p - modify alpha scaler.
tol - tolerence. the iterative method will stop when ||gradient|| < tol"""
xk = x0
k = 0 # iteration number
alpha_original = alpha
if save_xk:
xk_arr = np.array([xk])
while np.linalg.norm(rosenbrock_gradient(xk)) > tol:
""" find the next iteration xk+1"""
gradient = rosenbrock_gradient(xk)
if method == "sd":
pk = pk_steepest_descent(gradient)
if method == "newton":
hessian = rosenbrock_hessian(xk)
pk = pk_newton(gradient, hessian)
if print_num is not None:
if 0 <= k <= 6:
if k == 0:
print("***The first 6 iterations:*** \n")
print("Iteration #" + str(k) + ", x" + str(k) + " = " + str(xk))
print("||gradient|| = " + str(np.linalg.norm(gradient)))
print("f = " + str(rosenbrock_fun(xk)) + "\n")
if print_num - 5 <= k <= print_num and k > 6:
if k == print_num - 5 or k == 7:
print("***The last 6 iterations:*** \n")
print("Iteration #" + str(k) + ", x" + str(k) + " = " + str(xk))
print("||gradient|| = " + str(np.linalg.norm(gradient)))
print("f = " + str(rosenbrock_fun(xk)) + "\n")
xk_next = xk + alpha * pk
while rosenbrock_fun(xk_next) > rosenbrock_fun(xk) + c1 * alpha * np.matmul(pk.T, gradient):
""" find a step size that will satisfy Armijo-Goldstein inequality. Modify alpha. """
# print("call line search")
if k > 1:
old_x = xk_arr[-4:-2]
else:
old_x = None
alpha = my_line_search(c1=c1, c2=c2, pk=pk, xk=xk, old_x=old_x, alpha_0=0, alpha_max=1, method=method)
xk_next = xk + alpha * pk
xk = xk_next
alpha = alpha_original
k = k + 1
if save_xk:
xk_arr = np.append(xk_arr, [xk])
print("Iteration #" + str(k) + ", x" + str(k) + " = " + str(xk))
print("||gradient|| = " + str(np.linalg.norm(rosenbrock_gradient(xk))))
print("f = " + str(rosenbrock_fun(xk)) + "\n")
if save_xk:
return xk, k, xk_arr
return xk, k
if __name__ == "__main__":
res_2_sd = find_local_minimum(x0=[1.2, 1.2], c1=1e-4, c2=0.9, alpha=1, p=0.5, tol=1e-8, print_num=23, method="sd",
save_xk=True)
f_res_2_sd = np.ones(int(len(res_2_sd[-1]) / 2))
for ii in range(0, int(len(res_2_sd[-1]) / 2)):
f_res_2_sd[ii] = rosenbrock_fun([res_2_sd[-1][2 * ii], res_2_sd[-1][2 * ii + 1]])
fig, ax = plt.subplots(1, 1)
ax.scatter(np.arange(len(f_res_2_sd)), np.log10(f_res_2_sd), 2)
ax.set_title("Rosenbrock function, ic = [-1.2, 1], SD.")
ax.set_xlabel("# of iterations")
ax.set_ylabel("log10(f)")
plt.show()