np.linalg.norm

[henon]

I am going to port np.linalg.norm(...)

[Oceania2018]

It's not same as ?

[henon]

ok, you are right. that implements the L2 norm I need. I'll add the shortcut np.linalg.norm(...) just for Python compatibility

[henon]

no, after checking the code against the numpy docs, actually, the 2-norm is not the same what has been implemented in normalize(). There is no squaring of coefficients. Is that a bug?

https://het.as.utexas.edu/HET/Software/Numpy/reference/generated/numpy.linalg.norm.html

[Oceania2018]

Yes, they're different.

[8]

Hi,

I also noticed that the function is missing in 0.20.5.
I think one could add a shortcut from np.linalg.norm(a) => np.sqrt(a.dot(a)) instead, which should be equivalent.
Not sure about the overloads though.

Does this make sense to you?

Take care,
Martin