KeyType in example is invalid

[RileyAtWork]

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In 0.11 KeyType only takes 1 parameter - 'ulong count'
class MatrixElement
{
// Matrix column index starts from firstColumnIndex and is at most firstColumnIndex+n-1.
// Contieuous=true means that all values from firstColumnIndex to firstColumnIndex+n-1 are allowed keys.
// [KeyType(Contiguous = true, Count = n, Min = firstColumnIndex)]
// public uint MatrixColumnIndex;
// Matrix row index starts from firstRowIndex and is at most firstRowIndex+m-1.
// Contieuous=true means that all values from firstRowIndex to firstRowIndex+m-1 are allowed keys.
[KeyType(Contiguous = true, Count = m, Min = firstRowIndex)]
public uint MatrixRowIndex;
// The rating at the MatrixColumnIndex-th column and the MatrixRowIndex-th row.
public float Value;
}

Document Details

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• ID: 335e2f1c-de96-9963-8edc-c45bc5d31105
• Version Independent ID: 571d5df2-bce7-9fdf-c123-5c932d7935ce
• Content: MatrixFactorizationTrainer Class (Microsoft.ML.Trainers)
• Content Source: dotnet/xml/Microsoft.ML.Trainers/MatrixFactorizationTrainer.xml
• Product: dotnet-ml-api
• GitHub Login: @sfilipi
• Microsoft Alias: johalex

[wschin]

You're right. It should become something like this.

       // The following variables defines the shape of a (m+firstRowIndex)-by-(n+firstColumnIndex) matrix.
       const int firstRowIndex = 1;
       const int firstColumnIndex = 1;
       const int m = 60;
       const int n = 100;

       // A tuple of row index, column index, and rating. It specifies a value in the rating matrix.
       class MatrixElement
       {
           // Matrix column index starts from 0 and is at most firstColumnIndex+n-1.
           [KeyType(n + firstColumnIndex)]
           public uint MatrixColumnIndex;
           // Matrix row index starts from 0 and is at most firstRowIndex+m-1.
           [KeyType(m + firstRowIndex)]
           public uint MatrixRowIndex;
           // The rating at the MatrixColumnIndex-th column and the MatrixRowIndex-th row.
           public float Value;
       }

Basically, we now assume Contiguous is always true and Min is always zero.