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lua - escape fenced code correctly at line beginning (#14177) #14180

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lua - escape fenced code correctly at line beginning (#14177) #14180

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251360a
lua - escape fenced code correctly at line beginning (#14177)
cscheid Mar 9, 2026
a38b543
better fix to avoid regression
cscheid Mar 9, 2026
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better fix to avoid regression
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@cscheid
cscheid committed Mar 9, 2026
commit a38b543ef175de0bd227adfa52c5556a2f7703a1
13 changes: 10 additions & 3 deletions src/resources/filters/quarto-pre/engine-escape.lua
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Expand Up @@ -7,8 +7,14 @@ function engine_escape()
-- Line-by-line replacement for the pattern (\n?[^`\n]+`+){({+([^<}]+)}+)}
-- which suffers from O(n^2) backtracking on long lines without backticks.
-- See https://github.com/quarto-dev/quarto-cli/issues/14156

local line_pattern = "([^`\n]*`+)" .. patterns.engine_escape
-- Start-of-line fix for https://github.com/quarto-dev/quarto-cli/issues/14177
--
-- Two patterns for inline engine escape replacement:
-- 1. Start-of-line: match 1-2 backticks only (inline code, not code fences)
-- 2. Mid-line: match any backticks preceded by non-backtick text
-- This avoids over-processing code fence patterns (```{{engine}}) produced by step 2.
local sol_pattern = "^(``?)" .. patterns.engine_escape
local mid_pattern = "([^`\n]+`+)" .. patterns.engine_escape
local function unescape_inline_engine_codes(text)
if not text:find("{{", 1, true) then
return text
Expand All @@ -27,7 +33,8 @@ function engine_escape()
pos = len + 1
end
if line:find("`", 1, true) and line:find("{{", 1, true) then
line = line:gsub(line_pattern, "%1%2")
line = line:gsub(sol_pattern, "%1%2")
line = line:gsub(mid_pattern, "%1%2")
end
result[#result + 1] = line
end
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