Skip to content

Properly validate ref.cast when lacking a common supertype #6741

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
kripken merged 5 commits into from
Jul 23, 2024
Merged

Properly validate ref.cast when lacking a common supertype #6741

Changes from 1 commit
Commits
Show all changes
5 commits
Select commit Hold shift + click to select a range
7530b27
fix
kripken Jul 12, 2024
38e1ba9
fix
kripken Jul 12, 2024
6006c19
Merge remote-tracking branch 'origin/main' into ref.cast.val.unreach
kripken Jul 23, 2024
3abe58a
feedback: add test
kripken Jul 23, 2024
459552f
format
kripken Jul 23, 2024
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
Prev Previous commit
Next Next commit
fix
  • Loading branch information
@kripken
kripken committed Jul 12, 2024
commit 38e1ba971f3adae6d8f5e37fb151e95460dc3441
7 changes: 5 additions & 2 deletions src/wasm/wasm-validator.cpp
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -2753,8 +2753,11 @@ void FunctionValidator::visitRefCast(RefCast* curr) {
// earlier), then the cast is unreachable because the cast type had no
// common supertype with the ref, which is invalid. This is the same as the
// check below us, but we must do it first (as getHeapType fails otherwise).
if (!shouldBeUnequal(curr->type, Type(Type::unreachable), curr,
"ref.cast target type and ref type must have a common supertype")) {
if (!shouldBeUnequal(
Copy link
Member

@tlively tlively Jul 12, 2024

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

We could tighten this up even more by checking that the result type is a reference type. So if it somehow was set to i32 or something, we would still avoid the assertion failure.

Copy link
Member Author

@kripken kripken Jul 23, 2024

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Sounds good, I added that now as an extra test (it has a more generic error message, and I didn't want to lose the specific explanation for the supertype issue).

curr->type,
Type(Type::unreachable),
curr,
"ref.cast target type and ref type must have a common supertype")) {
return;
}
shouldBeEqual(
Expand Down